lab08: init
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8
lab08/applyMaybe.hs
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8
lab08/applyMaybe.hs
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applyMaybe :: Maybe a -> (a -> Maybe b) -> Maybe b
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applyMaybe Nothing f = Nothing
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applyMaybe (Just x) f = f x
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test1 = Just 3 `applyMaybe` (\x -> Just $ x * 2) `applyMaybe` (\x -> Just $ x - 1)
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test2 = Just 3 `applyMaybe` (\_ -> Nothing) `applyMaybe` (\x -> Just $ x - 1)
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15
lab08/bender.hs
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15
lab08/bender.hs
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type Pos = (Int, Int)
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start = (0,0)
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up (x, y) = (x, y+1)
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down (x, y) = (x, y-1)
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left (x, y) = (x-1, y)
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right (x, y) = (x+1, y)
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x -: f = f x
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-- Using the "-:" operator, we can chain movements together
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test1 = start -: up -: right
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test2 = start -: up -: left -: left -: right -: down
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34
lab08/benderPerhaps.hs
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34
lab08/benderPerhaps.hs
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import Data.Map (Map)
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import qualified Data.Map as Map
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-- In this code, we model bender moving around, but
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-- if he finds beer, he will stop responding to commands.
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type Pos = (Integer, Integer)
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x -: f = f x
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start = (0,0)
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badPos = Map.empty
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-: Map.insert (0,2) True
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-: Map.insert (-1,3) True
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-: Map.insert (-3,-8) True
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moveTo :: Pos -> Maybe Pos
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moveTo p =
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if Map.member p badPos
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then Nothing
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else Just p
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up (x, y) = moveTo (x, y+1)
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down (x, y) = moveTo (x, y-1)
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left (x, y) = moveTo (x-1, y)
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right (x, y) = moveTo (x+1, y)
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-- Our directions now result in Maybe Pos values, so we can't chain them with "-:" anymore.
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test1 = return start >>= up >>= right
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test2 = return start >>= up >>= left >>= left >>= right >>= down
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test3 = return start >>= left >>= left >>= up >>= up >>= right >>= up >>= right >>= right >>= down
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21
lab08/doit.hs
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21
lab08/doit.hs
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mydiv x y =
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x >>= (\numer ->
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y >>= (\denom ->
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if denom > 0
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then Just $ numer `div` denom
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else Nothing))
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mydiv' x y = do
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numer <- x
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denom <- y
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if denom > 0
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then return $ numer `div` denom
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else Nothing
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test1 = (Just 99) `mydiv` (Just 11)
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test1' = (Just 99) `mydiv'` (Just 11)
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test2 = (Just 9) `mydiv` (Just 0)
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test2' = (Just 9) `mydiv'` (Just 0)
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80
lab08/monadLab.lhs
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80
lab08/monadLab.lhs
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Below we have some mathematical binary arguments that you may recognize from homework 2.
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> data Binop =
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> Plus -- + :: Int -> Int -> Int
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> | Minus -- - :: Int -> Int -> Int
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> | Times -- * :: Int -> Int -> Int
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> | Divide -- / :: Int -> Int -> Int
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> deriving (Show)
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applyOp performs these operations, but unlike in the homework,
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you now must consider errors (represented by 'Nothing').
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> applyOp :: Binop -> Maybe Int -> Maybe Int -> Maybe Int
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Plus is done for you. Notice how code must check for 'Nothing'
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for each operand.
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> applyOp Plus mi mj =
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> case mi of
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> Nothing -> Nothing
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> Just i ->
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> case mj of
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> Nothing -> Nothing
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> Just j -> Just $ i + j
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Minus is also done for you. This case **does** use monads,
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but without the do syntax.
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> applyOp Minus mi mj =
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> mi >>= (\i -> mj >>= (\j -> Just $ i - j))
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Implement Times and Divide. Try the Times case without monads (as we did with
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the Plus case).
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> applyOp Times mi mj = error "TBD"
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For the Divide case, use bind (>>=) as we did for Minus.
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On an attempt to divide by 0, return Nothing as the answer.
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> applyOp Divide mi mj = error "TBD"
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The following test cases will help you verify your changes.
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> testapp1 = applyOp Minus (applyOp Times (Just 3) (Just 4)) $ applyOp Divide (Just 8) (Just 2)
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> testapp2 = applyOp Minus (applyOp Times (Just 3) (Just 4)) $ applyOp Divide (Just 8) (applyOp Plus (Just 3) (Just (-3)))
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Now implement applyOp', which implements all methods using the do syntax.
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The Plus case is done for you once again. Be sure to check for zero with Divide.
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> applyOp' :: Binop -> Maybe Int -> Maybe Int -> Maybe Int
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> applyOp' Plus mi mj = do
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> i <- mi
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> j <- mj
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> return $ i + j
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> applyOp' Minus mi mj = error "TBD"
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> applyOp' Times mi mj = error "TBD"
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> applyOp' Divide mi mj = error "TBD"
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More test cases:
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> testapp1' = applyOp' Minus (applyOp' Times (Just 3) (Just 4)) $ applyOp' Divide (Just 8) (Just 2)
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> testapp2' = applyOp' Minus (applyOp' Times (Just 3) (Just 4)) $ applyOp' Divide (Just 8) (applyOp' Plus (Just 3) (Just (-3)))
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Finally, note the following function for incrementing and decrementing ints.
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> mincr :: Int -> Maybe Int
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> mincr i = Just $ i + 1
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> mdecr :: Int -> Maybe Int
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> mdecr i = Just $ i - 1
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Experiment with these functions and the >>= syntax.
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Here is one example:
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> testIncDec = Just 7 >>= mincr >>= mincr >>= mincr >>= mdecr
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Does bind seem more natural in this case than using do? Why or why not?
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29
lab08/stack.hs
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29
lab08/stack.hs
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import Control.Monad.State
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type Stack = [Int]
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pop :: Stack -> (Int,Stack)
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pop (x:xs) = (x,xs)
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push :: Int -> Stack -> ((),Stack)
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push a xs = ((),a:xs)
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stackManip :: Stack -> (Int, Stack)
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stackManip stack = let
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((),newStack1) = push 3 stack
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(a ,newStack2) = pop newStack1
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in pop newStack2
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pop' :: State Stack Int
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pop' = State $ \(x:xs) -> (x,xs)
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push' :: Int -> State Stack ()
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push' a = State $ \xs -> ((),a:xs)
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stackManip' :: State Stack Int
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stackManip' = do
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push' 3
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a <- pop'
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pop'
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